401310313133 has 4 divisors (see below), whose sum is σ = 401820238080. Its totient is φ = 400800388188.

The previous prime is 401310313121. The next prime is 401310313139. The reversal of 401310313133 is 331313013104.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-401310313133 is a prime.

It is a super-2 number, since 2×401310313133² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 401310313099 and 401310313108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (401310313139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 254961293 + ... + 254962866.

It is an arithmetic number, because the mean of its divisors is an integer number (100455059520).

Almost surely, 2^401310313133 is an apocalyptic number.

It is an amenable number.

401310313133 is a deficient number, since it is larger than the sum of its proper divisors (509924947).

401310313133 is an equidigital number, since it uses as much as digits as its factorization.

401310313133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 509924946.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 401310313133 its reverse (331313013104), we get a palindrome (732623326237).

The spelling of 401310313133 in words is "four hundred one billion, three hundred ten million, three hundred thirteen thousand, one hundred thirty-three".