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401310314113 is a prime number
BaseRepresentation
bin1011101011011111111…
…01010110111010000001
31102100212000011020001011
411311233331112322001
523033340420022423
6504205344440521
740664562246532
oct5655775267201
91370760136034
10401310314113
11145216234825
126593a019141
132bac6c47b37
14155d020a689
15a68b974b0d
hex5d6ff56e81

401310314113 has 2 divisors, whose sum is σ = 401310314114. Its totient is φ = 401310314112.

The previous prime is 401310314089. The next prime is 401310314143. The reversal of 401310314113 is 311413013104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 364975473424 + 36334840689 = 604132^2 + 190617^2 .

It is a cyclic number.

It is not a de Polignac number, because 401310314113 - 229 = 400773443201 is a prime.

It is a super-2 number, since 2×4013103141132 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (401310314143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200655157056 + 200655157057.

It is an arithmetic number, because the mean of its divisors is an integer number (200655157057).

Almost surely, 2401310314113 is an apocalyptic number.

It is an amenable number.

401310314113 is a deficient number, since it is larger than the sum of its proper divisors (1).

401310314113 is an equidigital number, since it uses as much as digits as its factorization.

401310314113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 401310314113 its reverse (311413013104), we get a palindrome (712723327217).

The spelling of 401310314113 in words is "four hundred one billion, three hundred ten million, three hundred fourteen thousand, one hundred thirteen".