Base | Representation |
---|---|
bin | 1011101011011111111… |
… | …01010110111010000001 |
3 | 1102100212000011020001011 |
4 | 11311233331112322001 |
5 | 23033340420022423 |
6 | 504205344440521 |
7 | 40664562246532 |
oct | 5655775267201 |
9 | 1370760136034 |
10 | 401310314113 |
11 | 145216234825 |
12 | 6593a019141 |
13 | 2bac6c47b37 |
14 | 155d020a689 |
15 | a68b974b0d |
hex | 5d6ff56e81 |
401310314113 has 2 divisors, whose sum is σ = 401310314114. Its totient is φ = 401310314112.
The previous prime is 401310314089. The next prime is 401310314143. The reversal of 401310314113 is 311413013104.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 364975473424 + 36334840689 = 604132^2 + 190617^2 .
It is a cyclic number.
It is not a de Polignac number, because 401310314113 - 229 = 400773443201 is a prime.
It is a super-2 number, since 2×4013103141132 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (401310314143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200655157056 + 200655157057.
It is an arithmetic number, because the mean of its divisors is an integer number (200655157057).
Almost surely, 2401310314113 is an apocalyptic number.
It is an amenable number.
401310314113 is a deficient number, since it is larger than the sum of its proper divisors (1).
401310314113 is an equidigital number, since it uses as much as digits as its factorization.
401310314113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 401310314113 its reverse (311413013104), we get a palindrome (712723327217).
The spelling of 401310314113 in words is "four hundred one billion, three hundred ten million, three hundred fourteen thousand, one hundred thirteen".
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