4013105081 has 2 divisors, whose sum is σ = 4013105082. Its totient is φ = 4013105080.

The previous prime is 4013104987. The next prime is 4013105087. The reversal of 4013105081 is 1805013104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3562179856 + 450925225 = 59684^2 + 21235^2 .

It is a cyclic number.

It is not a de Polignac number, because 4013105081 - 2¹⁸ = 4012842937 is a prime.

It is a super-2 number, since 2×4013105081² = 32210024782296033122, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4013105087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006552540 + 2006552541.

It is an arithmetic number, because the mean of its divisors is an integer number (2006552541).

Almost surely, 2^4013105081 is an apocalyptic number.

It is an amenable number.

4013105081 is a deficient number, since it is larger than the sum of its proper divisors (1).

4013105081 is an equidigital number, since it uses as much as digits as its factorization.

4013105081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 480, while the sum is 23.

The square root of 4013105081 is about 63349.0732449970. The cubic root of 4013105081 is about 1589.1327471229.

Adding to 4013105081 its reverse (1805013104), we get a palindrome (5818118185).

The spelling of 4013105081 in words is "four billion, thirteen million, one hundred five thousand, eighty-one".