Base | Representation |
---|---|
bin | 101101100111111010111111… |
… | …1100110110010111111010001 |
3 | 1221121220221211121021012202110 |
4 | 1123033311333212302333101 |
5 | 410100034412012104410 |
6 | 3541303421153135533 |
7 | 150346522460010435 |
oct | 13317657746627721 |
9 | 1847827747235673 |
10 | 401311000113105 |
11 | 106963048453655 |
12 | 39014915b5a5a9 |
13 | 142c06075ac154 |
14 | 71157adad29c5 |
15 | 315e047b16720 |
hex | 16cfd7f9b2fd1 |
401311000113105 has 64 divisors (see below), whose sum is σ = 653134127348736. Its totient is φ = 210385212960000.
The previous prime is 401311000113071. The next prime is 401311000113161. The reversal of 401311000113105 is 501311000113104.
It is not a de Polignac number, because 401311000113105 - 218 = 401310999850961 is a prime.
It is a super-2 number, since 2×4013110001131052 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1602228130 + ... + 1602478580.
It is an arithmetic number, because the mean of its divisors is an integer number (10205220739824).
Almost surely, 2401311000113105 is an apocalyptic number.
It is an amenable number.
401311000113105 is a deficient number, since it is larger than the sum of its proper divisors (251823127235631).
401311000113105 is a wasteful number, since it uses less digits than its factorization.
401311000113105 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 258318.
The product of its (nonzero) digits is 180, while the sum is 21.
Adding to 401311000113105 its reverse (501311000113104), we get a palindrome (902622000226209).
Subtracting 401311000113105 from its reverse (501311000113104), we obtain a palindrome (99999999999999).
The spelling of 401311000113105 in words is "four hundred one trillion, three hundred eleven billion, one hundred thirteen thousand, one hundred five".
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