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40131241001041 is a prime number
BaseRepresentation
bin10010001111111110010000…
…10111010100000001010001
312021002111202012000122022211
421013333020113110001101
520230002240144013131
6221204012042232121
711311246364123641
oct1107771027240121
9167074665018284
1040131241001041
11118726223646a3
1246018534b5641
13195148a5bab28
149ca510708521
15498d8b9b95b1
hex247fc85d4051

40131241001041 has 2 divisors, whose sum is σ = 40131241001042. Its totient is φ = 40131241001040.

The previous prime is 40131241001011. The next prime is 40131241001053. The reversal of 40131241001041 is 14010014213104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 25801533589441 + 14329707411600 = 5079521^2 + 3785460^2 .

It is a cyclic number.

It is not a de Polignac number, because 40131241001041 - 229 = 40130704130129 is a prime.

It is a super-3 number, since 3×401312410010413 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (40131241001011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20065620500520 + 20065620500521.

It is an arithmetic number, because the mean of its divisors is an integer number (20065620500521).

Almost surely, 240131241001041 is an apocalyptic number.

It is an amenable number.

40131241001041 is a deficient number, since it is larger than the sum of its proper divisors (1).

40131241001041 is an equidigital number, since it uses as much as digits as its factorization.

40131241001041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 40131241001041 its reverse (14010014213104), we get a palindrome (54141255214145).

The spelling of 40131241001041 in words is "forty trillion, one hundred thirty-one billion, two hundred forty-one million, one thousand, forty-one".