Base | Representation |
---|---|
bin | 100101011000000000… |
… | …101010100111110011 |
3 | 10211120211002000021211 |
4 | 211120000222213303 |
5 | 1124142101302001 |
6 | 30234104300551 |
7 | 2620330132324 |
oct | 453000524763 |
9 | 124524060254 |
10 | 40131275251 |
11 | 16024071091 |
12 | 793ba71757 |
13 | 3a27326622 |
14 | 1d29bc044b |
15 | 109d2b8351 |
hex | 95802a9f3 |
40131275251 has 2 divisors, whose sum is σ = 40131275252. Its totient is φ = 40131275250.
The previous prime is 40131275237. The next prime is 40131275279. The reversal of 40131275251 is 15257213104.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40131275251 - 219 = 40130750963 is a prime.
It is a super-2 number, since 2×401312752512 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (40131275651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20065637625 + 20065637626.
It is an arithmetic number, because the mean of its divisors is an integer number (20065637626).
Almost surely, 240131275251 is an apocalyptic number.
40131275251 is a deficient number, since it is larger than the sum of its proper divisors (1).
40131275251 is an equidigital number, since it uses as much as digits as its factorization.
40131275251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8400, while the sum is 31.
Adding to 40131275251 its reverse (15257213104), we get a palindrome (55388488355).
The spelling of 40131275251 in words is "forty billion, one hundred thirty-one million, two hundred seventy-five thousand, two hundred fifty-one".
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