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401313043601 is a prime number
BaseRepresentation
bin1011101011100000001…
…11110001010010010001
31102100212012021220012022
411311300013301102101
523033342114343401
6504205523141225
740664624405321
oct5656007612221
91370765256168
10401313043601
111452178294a8
126593ab14815
132bac7692312
14155d071b281
15a68bd1371b
hex5d701f1491

401313043601 has 2 divisors, whose sum is σ = 401313043602. Its totient is φ = 401313043600.

The previous prime is 401313043589. The next prime is 401313043633. The reversal of 401313043601 is 106340313104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 333796218001 + 67516825600 = 577751^2 + 259840^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-401313043601 is a prime.

It is a super-2 number, since 2×4013130436012 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (401313043801) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200656521800 + 200656521801.

It is an arithmetic number, because the mean of its divisors is an integer number (200656521801).

Almost surely, 2401313043601 is an apocalyptic number.

It is an amenable number.

401313043601 is a deficient number, since it is larger than the sum of its proper divisors (1).

401313043601 is an equidigital number, since it uses as much as digits as its factorization.

401313043601 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 401313043601 its reverse (106340313104), we get a palindrome (507653356705).

The spelling of 401313043601 in words is "four hundred one billion, three hundred thirteen million, forty-three thousand, six hundred one".