Base | Representation |
---|---|
bin | 1011101011100000001… |
… | …11110001010010010001 |
3 | 1102100212012021220012022 |
4 | 11311300013301102101 |
5 | 23033342114343401 |
6 | 504205523141225 |
7 | 40664624405321 |
oct | 5656007612221 |
9 | 1370765256168 |
10 | 401313043601 |
11 | 1452178294a8 |
12 | 6593ab14815 |
13 | 2bac7692312 |
14 | 155d071b281 |
15 | a68bd1371b |
hex | 5d701f1491 |
401313043601 has 2 divisors, whose sum is σ = 401313043602. Its totient is φ = 401313043600.
The previous prime is 401313043589. The next prime is 401313043633. The reversal of 401313043601 is 106340313104.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 333796218001 + 67516825600 = 577751^2 + 259840^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-401313043601 is a prime.
It is a super-2 number, since 2×4013130436012 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (401313043801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200656521800 + 200656521801.
It is an arithmetic number, because the mean of its divisors is an integer number (200656521801).
Almost surely, 2401313043601 is an apocalyptic number.
It is an amenable number.
401313043601 is a deficient number, since it is larger than the sum of its proper divisors (1).
401313043601 is an equidigital number, since it uses as much as digits as its factorization.
401313043601 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 401313043601 its reverse (106340313104), we get a palindrome (507653356705).
The spelling of 401313043601 in words is "four hundred one billion, three hundred thirteen million, forty-three thousand, six hundred one".
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