4013134242301 has 8 divisors (see below), whose sum is σ = 4024970830080. Its totient is φ = 4001312065632.

The previous prime is 4013134242197. The next prime is 4013134242317. The reversal of 4013134242301 is 1032424313104.

It is a happy number.

4013134242301 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 4013134242301 - 2²¹ = 4013132145149 is a prime.

It is a super-2 number, since 2×4013134242301² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 4013134242301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4013134242391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3044880 + ... + 4159033.

It is an arithmetic number, because the mean of its divisors is an integer number (503121353760).

Almost surely, 2^{4013134242301} is an apocalyptic number.

It is an amenable number.

4013134242301 is a deficient number, since it is larger than the sum of its proper divisors (11836587779).

4013134242301 is a wasteful number, since it uses less digits than its factorization.

4013134242301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7205555.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 4013134242301 its reverse (1032424313104), we get a palindrome (5045558555405).

The spelling of 4013134242301 in words is "four trillion, thirteen billion, one hundred thirty-four million, two hundred forty-two thousand, three hundred one".