Base | Representation |
---|---|
bin | 111010011001100010000… |
… | …101110110011110100011 |
3 | 112012122121222121210021221 |
4 | 322121202011312132203 |
5 | 1011222410124433431 |
6 | 12311340300155511 |
7 | 562640322662443 |
oct | 72314205663643 |
9 | 15178558553257 |
10 | 4013145155491 |
11 | 1307a688aa53a |
12 | 549936238b97 |
13 | 231590291254 |
14 | dc347092123 |
15 | 6e5d0031111 |
hex | 3a6621767a3 |
4013145155491 has 2 divisors, whose sum is σ = 4013145155492. Its totient is φ = 4013145155490.
The previous prime is 4013145155441. The next prime is 4013145155507. The reversal of 4013145155491 is 1945515413104.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4013145155491 - 217 = 4013145024419 is a prime.
It is a super-2 number, since 2×40131451554912 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4013145155401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006572577745 + 2006572577746.
It is an arithmetic number, because the mean of its divisors is an integer number (2006572577746).
Almost surely, 24013145155491 is an apocalyptic number.
4013145155491 is a deficient number, since it is larger than the sum of its proper divisors (1).
4013145155491 is an equidigital number, since it uses as much as digits as its factorization.
4013145155491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216000, while the sum is 43.
The spelling of 4013145155491 in words is "four trillion, thirteen billion, one hundred forty-five million, one hundred fifty-five thousand, four hundred ninety-one".
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