4013153355413 has 4 divisors (see below), whose sum is σ = 4040087270700. Its totient is φ = 3986219440128.

The previous prime is 4013153355391. The next prime is 4013153355457. The reversal of 4013153355413 is 3145533513104.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1604179299844 + 2408974055569 = 1266562^2 + 1552087^2 .

It is a cyclic number.

It is not a de Polignac number, because 4013153355413 - 2⁶ = 4013153355349 is a prime.

It is a super-2 number, since 2×4013153355413² (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4013153355493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13466957420 + ... + 13466957717.

It is an arithmetic number, because the mean of its divisors is an integer number (1010021817675).

Almost surely, 2^{4013153355413} is an apocalyptic number.

It is an amenable number.

4013153355413 is a deficient number, since it is larger than the sum of its proper divisors (26933915287).

4013153355413 is a wasteful number, since it uses less digits than its factorization.

4013153355413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26933915286.

The product of its (nonzero) digits is 162000, while the sum is 38.

Adding to 4013153355413 its reverse (3145533513104), we get a palindrome (7158686868517).

The spelling of 4013153355413 in words is "four trillion, thirteen billion, one hundred fifty-three million, three hundred fifty-five thousand, four hundred thirteen".