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40131772054721 is a prime number
BaseRepresentation
bin10010001111111111010000…
…00001000111110011000001
312021002120010012021222000122
421013333220001013303001
520230004332121222341
6221204140452430025
711311265503035254
oct1107775001076301
9167076105258018
1040131772054721
1111872875101136
124601981318315
131951543626689
149ca56106509b
15498dbd41894b
hex247fe8047cc1

40131772054721 has 2 divisors, whose sum is σ = 40131772054722. Its totient is φ = 40131772054720.

The previous prime is 40131772054679. The next prime is 40131772054807. The reversal of 40131772054721 is 12745027713104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 36484680465025 + 3647091589696 = 6040255^2 + 1909736^2 .

It is a cyclic number.

It is not a de Polignac number, because 40131772054721 - 26 = 40131772054657 is a prime.

It is a super-2 number, since 2×401317720547212 (a number of 28 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (40131772354721) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20065886027360 + 20065886027361.

It is an arithmetic number, because the mean of its divisors is an integer number (20065886027361).

Almost surely, 240131772054721 is an apocalyptic number.

It is an amenable number.

40131772054721 is a deficient number, since it is larger than the sum of its proper divisors (1).

40131772054721 is an equidigital number, since it uses as much as digits as its factorization.

40131772054721 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 329280, while the sum is 44.

Adding to 40131772054721 its reverse (12745027713104), we get a palindrome (52876799767825).

The spelling of 40131772054721 in words is "forty trillion, one hundred thirty-one billion, seven hundred seventy-two million, fifty-four thousand, seven hundred twenty-one".