40132022023105 has 4 divisors (see below), whose sum is σ = 48158426427732. Its totient is φ = 32105617618480.

The previous prime is 40132022023103. The next prime is 40132022023133. The reversal of 40132022023105 is 50132022023104.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 17530022750769 + 22601999272336 = 4186887^2 + 4754156^2 .

It is not a de Polignac number, because 40132022023105 - 2¹ = 40132022023103 is a prime.

It is a super-2 number, since 2×40132022023105² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 40132022023105.

It is not an unprimeable number, because it can be changed into a prime (40132022023103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4013202202306 + ... + 4013202202315.

It is an arithmetic number, because the mean of its divisors is an integer number (12039606606933).

Almost surely, 2^{40132022023105} is an apocalyptic number.

It is an amenable number.

40132022023105 is a deficient number, since it is larger than the sum of its proper divisors (8026404404627).

40132022023105 is an equidigital number, since it uses as much as digits as its factorization.

40132022023105 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8026404404626.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 40132022023105 its reverse (50132022023104), we get a palindrome (90264044046209).

Subtracting 40132022023105 from its reverse (50132022023104), we obtain a palindrome (9999999999999).

The spelling of 40132022023105 in words is "forty trillion, one hundred thirty-two billion, twenty-two million, twenty-three thousand, one hundred five".