Base | Representation |
---|---|
bin | 10010001111111111101101… |
… | …11010101011001110111111 |
3 | 12021002120202121122200011212 |
4 | 21013333312322223032333 |
5 | 20230010340114214403 |
6 | 221204221342235035 |
7 | 11311304626526123 |
oct | 1107776672531677 |
9 | 167076677580155 |
10 | 40132022023103 |
11 | 1187299321307a |
12 | 4601a30b85a7b |
13 | 195158335786a |
14 | 9ca586333583 |
15 | 498dd53434d8 |
hex | 247ff6eab3bf |
40132022023103 has 2 divisors, whose sum is σ = 40132022023104. Its totient is φ = 40132022023102.
The previous prime is 40132022023087. The next prime is 40132022023133. The reversal of 40132022023103 is 30132022023104.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40132022023103 - 24 = 40132022023087 is a prime.
It is a super-2 number, since 2×401320220231032 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (40132022023133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20066011011551 + 20066011011552.
It is an arithmetic number, because the mean of its divisors is an integer number (20066011011552).
Almost surely, 240132022023103 is an apocalyptic number.
40132022023103 is a deficient number, since it is larger than the sum of its proper divisors (1).
40132022023103 is an equidigital number, since it uses as much as digits as its factorization.
40132022023103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 40132022023103 its reverse (30132022023104), we get a palindrome (70264044046207).
Subtracting from 40132022023103 its reverse (30132022023104), we obtain a palindrome (9999999999999).
The spelling of 40132022023103 in words is "forty trillion, one hundred thirty-two billion, twenty-two million, twenty-three thousand, one hundred three".
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