Base | Representation |
---|---|
bin | 111010011001100110101… |
… | …111100101000111101111 |
3 | 112012122211102111000202221 |
4 | 322121212233211013233 |
5 | 1011223040120001221 |
6 | 12311352125100211 |
7 | 562642261245220 |
oct | 72314657450757 |
9 | 15178742430687 |
10 | 4013223203311 |
11 | 1307aa8967a73 |
12 | 5499583b7667 |
13 | 2315a34b9baa |
14 | dc3535ab247 |
15 | 6e5d6ceb541 |
hex | 3a666be51ef |
4013223203311 has 4 divisors (see below), whose sum is σ = 4586540803792. Its totient is φ = 3439905602832.
The previous prime is 4013223203291. The next prime is 4013223203333. The reversal of 4013223203311 is 1133023223104.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 4013223203311 - 27 = 4013223203183 is a prime.
It is a super-2 number, since 2×40132232033112 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (4013223203411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 286658800230 + ... + 286658800243.
It is an arithmetic number, because the mean of its divisors is an integer number (1146635200948).
Almost surely, 24013223203311 is an apocalyptic number.
4013223203311 is a deficient number, since it is larger than the sum of its proper divisors (573317600481).
4013223203311 is an equidigital number, since it uses as much as digits as its factorization.
4013223203311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 573317600480.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 4013223203311 its reverse (1133023223104), we get a palindrome (5146246426415).
The spelling of 4013223203311 in words is "four trillion, thirteen billion, two hundred twenty-three million, two hundred three thousand, three hundred eleven".
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