Base | Representation |
---|---|
bin | 10010010000000000010010… |
… | …00110111001001001001011 |
3 | 12021002121112212221001201001 |
4 | 21020000021012321021023 |
5 | 20230012001231400231 |
6 | 221204311523435431 |
7 | 11311315323603334 |
oct | 1110001106711113 |
9 | 167077485831631 |
10 | 40132327215691 |
11 | 1187302a513857 |
12 | 4601ab7225b77 |
13 | 1951601652ca9 |
14 | 9ca5b4a9928b |
15 | 498e0202ab61 |
hex | 2480091b924b |
40132327215691 has 2 divisors, whose sum is σ = 40132327215692. Its totient is φ = 40132327215690.
The previous prime is 40132327215679. The next prime is 40132327215727. The reversal of 40132327215691 is 19651272323104.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 40132327215691 - 231 = 40130179732043 is a prime.
It is a super-2 number, since 2×401323272156912 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (40132327215611) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20066163607845 + 20066163607846.
It is an arithmetic number, because the mean of its divisors is an integer number (20066163607846).
Almost surely, 240132327215691 is an apocalyptic number.
40132327215691 is a deficient number, since it is larger than the sum of its proper divisors (1).
40132327215691 is an equidigital number, since it uses as much as digits as its factorization.
40132327215691 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 544320, while the sum is 46.
Adding to 40132327215691 its reverse (19651272323104), we get a palindrome (59783599538795).
The spelling of 40132327215691 in words is "forty trillion, one hundred thirty-two billion, three hundred twenty-seven million, two hundred fifteen thousand, six hundred ninety-one".
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