40133115151 has 4 divisors (see below), whose sum is σ = 40133926672. Its totient is φ = 40132303632.

The previous prime is 40133115131. The next prime is 40133115203. The reversal of 40133115151 is 15151133104.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 40133115151 - 2¹⁵ = 40133082383 is a prime.

It is a super-2 number, since 2×40133115151² (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40133115101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 326406 + ... + 432211.

It is an arithmetic number, because the mean of its divisors is an integer number (10033481668).

Almost surely, 2^40133115151 is an apocalyptic number.

40133115151 is a deficient number, since it is larger than the sum of its proper divisors (811521).

40133115151 is an equidigital number, since it uses as much as digits as its factorization.

40133115151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 811520.

The product of its (nonzero) digits is 900, while the sum is 25.

Adding to 40133115151 its reverse (15151133104), we get a palindrome (55284248255).

The spelling of 40133115151 in words is "forty billion, one hundred thirty-three million, one hundred fifteen thousand, one hundred fifty-one".