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401334130042 = 2401500416621
BaseRepresentation
bin1011101011100010110…
…00001101010101111010
31102100220122222012100121
411311301120031111322
523033413014130132
6504211555123454
740665301550656
oct5656130152572
91370818865317
10401334130042
1114522872100a
1265945ba358a
132bacbb660c1
14155d3449a66
15a68dacb497
hex5d7160d57a

401334130042 has 8 divisors (see below), whose sum is σ = 603502446132. Its totient is φ = 200166648000.

The previous prime is 401334130039. The next prime is 401334130049. The reversal of 401334130042 is 240031433104.

It can be written as a sum of positive squares in 2 ways, for example, as 295662975001 + 105671155041 = 543749^2 + 325071^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×4013341300422 (a number of 24 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 401334129989 and 401334130016.

It is not an unprimeable number, because it can be changed into a prime (401334130049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 250207509 + ... + 250209112.

Almost surely, 2401334130042 is an apocalyptic number.

401334130042 is a deficient number, since it is larger than the sum of its proper divisors (202168316090).

401334130042 is a wasteful number, since it uses less digits than its factorization.

401334130042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 500417024.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 401334130042 its reverse (240031433104), we get a palindrome (641365563146).

The spelling of 401334130042 in words is "four hundred one billion, three hundred thirty-four million, one hundred thirty thousand, forty-two".

Divisors: 1 2 401 802 500416621 1000833242 200667065021 401334130042