401344114304033 has 2 divisors, whose sum is σ = 401344114304034. Its totient is φ = 401344114304032.

The previous prime is 401344114303981. The next prime is 401344114304041. The reversal of 401344114304033 is 330403411443104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 295157107338769 + 106187006965264 = 17180137^2 + 10304708^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-401344114304033 is a prime.

It is a super-2 number, since 2×401344114304033² (a number of 30 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 401344114303984 and 401344114304002.

It is not a weakly prime, because it can be changed into another prime (401344114304053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 200672057152016 + 200672057152017.

It is an arithmetic number, because the mean of its divisors is an integer number (200672057152017).

Almost surely, 2^{401344114304033} is an apocalyptic number.

It is an amenable number.

401344114304033 is a deficient number, since it is larger than the sum of its proper divisors (1).

401344114304033 is an equidigital number, since it uses as much as digits as its factorization.

401344114304033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 401344114304033 its reverse (330403411443104), we get a palindrome (731747525747137).

The spelling of 401344114304033 in words is "four hundred one trillion, three hundred forty-four billion, one hundred fourteen million, three hundred four thousand, thirty-three".