Base | Representation |
---|---|
bin | 1011101011100011111… |
… | …11000011011010101100 |
3 | 1102100221101010112202100 |
4 | 11311301333003122230 |
5 | 23033423121004004 |
6 | 504213001255100 |
7 | 40665454241625 |
oct | 5656177033254 |
9 | 1370841115670 |
10 | 401344313004 |
11 | 145233446688 |
12 | 65949494490 |
13 | 2bb00cc001b |
14 | 155d493aa4c |
15 | a68e93d739 |
hex | 5d71fc36ac |
401344313004 has 18 divisors (see below), whose sum is σ = 1014509235740. Its totient is φ = 133781437656.
The previous prime is 401344312981. The next prime is 401344313011. The reversal of 401344313004 is 400313443104.
401344313004 is a `hidden beast` number, since 4 + 0 + 1 + 344 + 313 + 0 + 0 + 4 = 666.
It is a tau number, because it is divible by the number of its divisors (18).
It is a super-2 number, since 2×4013443130042 (a number of 24 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 5574226534 + ... + 5574226605.
Almost surely, 2401344313004 is an apocalyptic number.
It is an amenable number.
401344313004 is an abundant number, since it is smaller than the sum of its proper divisors (613164922736).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
401344313004 is a wasteful number, since it uses less digits than its factorization.
401344313004 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11148453149 (or 11148453144 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 401344313004 its reverse (400313443104), we get a palindrome (801657756108).
The spelling of 401344313004 in words is "four hundred one billion, three hundred forty-four million, three hundred thirteen thousand, four".
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