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40134465060433 is a prime number
BaseRepresentation
bin10010010000000100010001…
…00010000111111001010001
312021002211001212122211100221
421020002020202013321101
520230030341023413213
6221205304013113041
711311422313151002
oct1110021042077121
9167084055584327
1040134465060433
1111873a27250197
1246023b3188781
131951882531693
149ca7389971a9
15498ec9a6b38d
hex248088887e51

40134465060433 has 2 divisors, whose sum is σ = 40134465060434. Its totient is φ = 40134465060432.

The previous prime is 40134465060427. The next prime is 40134465060497. The reversal of 40134465060433 is 33406056443104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21739913361664 + 18394551698769 = 4662608^2 + 4288887^2 .

It is a cyclic number.

It is not a de Polignac number, because 40134465060433 - 241 = 37935441804881 is a prime.

It is a super-2 number, since 2×401344650604332 (a number of 28 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 40134465060433.

It is not a weakly prime, because it can be changed into another prime (40134465060413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20067232530216 + 20067232530217.

It is an arithmetic number, because the mean of its divisors is an integer number (20067232530217).

Almost surely, 240134465060433 is an apocalyptic number.

It is an amenable number.

40134465060433 is a deficient number, since it is larger than the sum of its proper divisors (1).

40134465060433 is an equidigital number, since it uses as much as digits as its factorization.

40134465060433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1244160, while the sum is 43.

The spelling of 40134465060433 in words is "forty trillion, one hundred thirty-four billion, four hundred sixty-five million, sixty thousand, four hundred thirty-three".