4013498273 has 2 divisors, whose sum is σ = 4013498274. Its totient is φ = 4013498272.

The previous prime is 4013498257. The next prime is 4013498311. The reversal of 4013498273 is 3728943104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3323753104 + 689745169 = 57652^2 + 26263^2 .

It is a cyclic number.

It is not a de Polignac number, because 4013498273 - 2⁴ = 4013498257 is a prime.

It is a super-2 number, since 2×4013498273² = 32216336774747965058, which contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 4013498273.

It is not a weakly prime, because it can be changed into another prime (4013498773) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006749136 + 2006749137.

It is an arithmetic number, because the mean of its divisors is an integer number (2006749137).

Almost surely, 2^4013498273 is an apocalyptic number.

It is an amenable number.

4013498273 is a deficient number, since it is larger than the sum of its proper divisors (1).

4013498273 is an equidigital number, since it uses as much as digits as its factorization.

4013498273 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 145152, while the sum is 41.

The square root of 4013498273 is about 63352.1765450880. The cubic root of 4013498273 is about 1589.1846449148.

The spelling of 4013498273 in words is "four billion, thirteen million, four hundred ninety-eight thousand, two hundred seventy-three".