Base | Representation |
---|---|
bin | 1110111100111001… |
… | …0010111000111011 |
3 | 101100201010000201122 |
4 | 3233032102320323 |
5 | 31204424031021 |
6 | 1502131135455 |
7 | 201313130021 |
oct | 35716227073 |
9 | 11321100648 |
10 | 4013502011 |
11 | 177a576512 |
12 | 94014458b |
13 | 4bc66b27c |
14 | 2a106a711 |
15 | 187540bab |
hex | ef392e3b |
4013502011 has 2 divisors, whose sum is σ = 4013502012. Its totient is φ = 4013502010.
The previous prime is 4013501981. The next prime is 4013502019. The reversal of 4013502011 is 1102053104.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4013502011 is a prime.
It is a super-2 number, since 2×40135020112 = 32216396784602088242, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4013502019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006751005 + 2006751006.
It is an arithmetic number, because the mean of its divisors is an integer number (2006751006).
Almost surely, 24013502011 is an apocalyptic number.
4013502011 is a deficient number, since it is larger than the sum of its proper divisors (1).
4013502011 is an equidigital number, since it uses as much as digits as its factorization.
4013502011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120, while the sum is 17.
The square root of 4013502011 is about 63352.2060468300. The cubic root of 4013502011 is about 1589.1851382808.
Adding to 4013502011 its reverse (1102053104), we get a palindrome (5115555115).
The spelling of 4013502011 in words is "four billion, thirteen million, five hundred two thousand, eleven".
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