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4013502011 is a prime number
BaseRepresentation
bin1110111100111001…
…0010111000111011
3101100201010000201122
43233032102320323
531204424031021
61502131135455
7201313130021
oct35716227073
911321100648
104013502011
11177a576512
1294014458b
134bc66b27c
142a106a711
15187540bab
hexef392e3b

4013502011 has 2 divisors, whose sum is σ = 4013502012. Its totient is φ = 4013502010.

The previous prime is 4013501981. The next prime is 4013502019. The reversal of 4013502011 is 1102053104.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4013502011 is a prime.

It is a super-2 number, since 2×40135020112 = 32216396784602088242, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4013502019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2006751005 + 2006751006.

It is an arithmetic number, because the mean of its divisors is an integer number (2006751006).

Almost surely, 24013502011 is an apocalyptic number.

4013502011 is a deficient number, since it is larger than the sum of its proper divisors (1).

4013502011 is an equidigital number, since it uses as much as digits as its factorization.

4013502011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 4013502011 is about 63352.2060468300. The cubic root of 4013502011 is about 1589.1851382808.

Adding to 4013502011 its reverse (1102053104), we get a palindrome (5115555115).

The spelling of 4013502011 in words is "four billion, thirteen million, five hundred two thousand, eleven".