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40136856803353 is a prime number
BaseRepresentation
bin10010010000001000101110…
…00101111001100000011001
312021010001020120010221212001
421020010113011321200121
520230100240320201403
6221210341212321001
711311535504504302
oct1110042705714031
9167101216127761
1040136856803353
1111874a44333032
124602960173161
131951b73bb8b8b
149ca8c44a77a9
154990b9a10c1d
hex248117179819

40136856803353 has 2 divisors, whose sum is σ = 40136856803354. Its totient is φ = 40136856803352.

The previous prime is 40136856803341. The next prime is 40136856803377. The reversal of 40136856803353 is 35330865863104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 37033030317529 + 3103826485824 = 6085477^2 + 1761768^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40136856803353 is a prime.

It is a super-2 number, since 2×401368568033532 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 40136856803294 and 40136856803303.

It is not a weakly prime, because it can be changed into another prime (40136856803333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20068428401676 + 20068428401677.

It is an arithmetic number, because the mean of its divisors is an integer number (20068428401677).

Almost surely, 240136856803353 is an apocalyptic number.

It is an amenable number.

40136856803353 is a deficient number, since it is larger than the sum of its proper divisors (1).

40136856803353 is an equidigital number, since it uses as much as digits as its factorization.

40136856803353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18662400, while the sum is 55.

The spelling of 40136856803353 in words is "forty trillion, one hundred thirty-six billion, eight hundred fifty-six million, eight hundred three thousand, three hundred fifty-three".