Base | Representation |
---|---|
bin | 10010010000001001000000… |
… | …11011011011011100101111 |
3 | 12021010001122110220001011102 |
4 | 21020010200123123130233 |
5 | 20230101100420123401 |
6 | 221210404525513315 |
7 | 11311542416064620 |
oct | 1110044033333457 |
9 | 167101573801142 |
10 | 40137013442351 |
11 | 1187501479a251 |
12 | 46029a471283b |
13 | 1951b9a4a0887 |
14 | 9ca8db1dda47 |
15 | 4990c865256b |
hex | 2481206db72f |
40137013442351 has 4 divisors (see below), whose sum is σ = 45870872505552. Its totient is φ = 34403154379152.
The previous prime is 40137013442321. The next prime is 40137013442363. The reversal of 40137013442351 is 15324431073104.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 40137013442351 - 226 = 40136946333487 is a prime.
It is a super-2 number, since 2×401370134423512 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (40137013442321) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2866929531590 + ... + 2866929531603.
It is an arithmetic number, because the mean of its divisors is an integer number (11467718126388).
Almost surely, 240137013442351 is an apocalyptic number.
40137013442351 is a deficient number, since it is larger than the sum of its proper divisors (5733859063201).
40137013442351 is an equidigital number, since it uses as much as digits as its factorization.
40137013442351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5733859063200.
The product of its (nonzero) digits is 120960, while the sum is 38.
The spelling of 40137013442351 in words is "forty trillion, one hundred thirty-seven billion, thirteen million, four hundred forty-two thousand, three hundred fifty-one".
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