4014113214113 has 2 divisors, whose sum is σ = 4014113214114. Its totient is φ = 4014113214112.

The previous prime is 4014113214103. The next prime is 4014113214149. The reversal of 4014113214113 is 3114123114104.

4014113214113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3468358696609 + 545754517504 = 1862353^2 + 738752^2 .

It is a cyclic number.

It is not a de Polignac number, because 4014113214113 - 2⁶ = 4014113214049 is a prime.

It is a super-2 number, since 2×4014113214113² (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4014113214103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2007056607056 + 2007056607057.

It is an arithmetic number, because the mean of its divisors is an integer number (2007056607057).

Almost surely, 2^{4014113214113} is an apocalyptic number.

It is an amenable number.

4014113214113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4014113214113 is an equidigital number, since it uses as much as digits as its factorization.

4014113214113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 26.

Adding to 4014113214113 its reverse (3114123114104), we get a palindrome (7128236328217).

The spelling of 4014113214113 in words is "four trillion, fourteen billion, one hundred thirteen million, two hundred fourteen thousand, one hundred thirteen".