Search a number
-
+
4014133202201 is a prime number
BaseRepresentation
bin111010011010011100111…
…110111100110100011001
3112012202011211210202120112
4322122130332330310121
51011231421044432301
612312022313334105
7563003651150213
oct72323476746431
915182154722515
104014133202201
1113084255a9671
12549b71107335
132316b9ba4785
14dc3dc3ab5b3
156e63bb509bb
hex3a69cfbcd19

4014133202201 has 2 divisors, whose sum is σ = 4014133202202. Its totient is φ = 4014133202200.

The previous prime is 4014133202197. The next prime is 4014133202237. The reversal of 4014133202201 is 1022023314104.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3973942575625 + 40190626576 = 1993475^2 + 200476^2 .

It is a cyclic number.

It is not a de Polignac number, because 4014133202201 - 22 = 4014133202197 is a prime.

It is a super-2 number, since 2×40141332022012 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4014133204201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2007066601100 + 2007066601101.

It is an arithmetic number, because the mean of its divisors is an integer number (2007066601101).

Almost surely, 24014133202201 is an apocalyptic number.

It is an amenable number.

4014133202201 is a deficient number, since it is larger than the sum of its proper divisors (1).

4014133202201 is an equidigital number, since it uses as much as digits as its factorization.

4014133202201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 4014133202201 its reverse (1022023314104), we get a palindrome (5036156516305).

The spelling of 4014133202201 in words is "four trillion, fourteen billion, one hundred thirty-three million, two hundred two thousand, two hundred one".