4014211231241 has 2 divisors, whose sum is σ = 4014211231242. Its totient is φ = 4014211231240.

The previous prime is 4014211231207. The next prime is 4014211231253. The reversal of 4014211231241 is 1421321124104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2659247718400 + 1354963512841 = 1630720^2 + 1164029^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-4014211231241 is a prime.

It is a super-2 number, since 2×4014211231241² (a number of 26 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 4014211231241.

It is not a weakly prime, because it can be changed into another prime (4014211231201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2007105615620 + 2007105615621.

It is an arithmetic number, because the mean of its divisors is an integer number (2007105615621).

Almost surely, 2^{4014211231241} is an apocalyptic number.

It is an amenable number.

4014211231241 is a deficient number, since it is larger than the sum of its proper divisors (1).

4014211231241 is an equidigital number, since it uses as much as digits as its factorization.

4014211231241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1536, while the sum is 26.

Adding to 4014211231241 its reverse (1421321124104), we get a palindrome (5435532355345).

The spelling of 4014211231241 in words is "four trillion, fourteen billion, two hundred eleven million, two hundred thirty-one thousand, two hundred forty-one".