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4014311022133 = 7575302920769
BaseRepresentation
bin111010011010100111100…
…101010001111000110101
3112012202122020101221122221
4322122213211101320311
51011232302110202013
612312052104522341
7563011240455526
oct72324745217065
915182566357587
104014311022133
111308506a12395
1254a0007803b1
13231717994279
14dc417c5884d
156e64c57808d
hex3a6a7951e35

4014311022133 has 4 divisors (see below), whose sum is σ = 4019613943660. Its totient is φ = 4009008100608.

The previous prime is 4014311022121. The next prime is 4014311022151. The reversal of 4014311022133 is 3312201134104.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1964322780849 + 2049988241284 = 1401543^2 + 1431778^2 .

It is a cyclic number.

It is not a de Polignac number, because 4014311022133 - 217 = 4014310891061 is a prime.

It is a super-2 number, since 2×40143110221332 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4014311022098 and 4014311022107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4014311022173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2651459628 + ... + 2651461141.

It is an arithmetic number, because the mean of its divisors is an integer number (1004903485915).

Almost surely, 24014311022133 is an apocalyptic number.

It is an amenable number.

4014311022133 is a deficient number, since it is larger than the sum of its proper divisors (5302921527).

4014311022133 is an equidigital number, since it uses as much as digits as its factorization.

4014311022133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5302921526.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 4014311022133 its reverse (3312201134104), we get a palindrome (7326512156237).

It can be divided in two parts, 40143 and 11022133, that added together give a square (11062276 = 33262).

The spelling of 4014311022133 in words is "four trillion, fourteen billion, three hundred eleven million, twenty-two thousand, one hundred thirty-three".

Divisors: 1 757 5302920769 4014311022133