Base | Representation |
---|---|
bin | 111010011010101001011… |
… | …001001111110101001011 |
3 | 112012202201100121110000011 |
4 | 322122221121033311023 |
5 | 1011232332401004121 |
6 | 12312055112252351 |
7 | 563012060042215 |
oct | 72325131176513 |
9 | 15182640543004 |
10 | 4014341422411 |
11 | 1308522096591 |
12 | 54a00a9a10b7 |
13 | 2317210794b8 |
14 | dc41bccd5b5 |
15 | 6e6500807e1 |
hex | 3a6a964fd4b |
4014341422411 has 2 divisors, whose sum is σ = 4014341422412. Its totient is φ = 4014341422410.
The previous prime is 4014341422391. The next prime is 4014341422433. The reversal of 4014341422411 is 1142241434104.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4014341422411 - 213 = 4014341414219 is a prime.
It is a super-2 number, since 2×40143414224112 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4014341422811) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2007170711205 + 2007170711206.
It is an arithmetic number, because the mean of its divisors is an integer number (2007170711206).
Almost surely, 24014341422411 is an apocalyptic number.
4014341422411 is a deficient number, since it is larger than the sum of its proper divisors (1).
4014341422411 is an equidigital number, since it uses as much as digits as its factorization.
4014341422411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12288, while the sum is 31.
Adding to 4014341422411 its reverse (1142241434104), we get a palindrome (5156582856515).
The spelling of 4014341422411 in words is "four trillion, fourteen billion, three hundred forty-one million, four hundred twenty-two thousand, four hundred eleven".
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