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40145728983 = 313381909661
BaseRepresentation
bin100101011000110111…
…110011010111010111
310211121211021100002020
4211120313303113113
51124204301311413
630235342144223
72620564031433
oct453067632727
9124554240066
1040145728983
1116031243418
127944882073
133a2a317429
141d2baa39c3
15109e6c0c23
hex958df35d7

40145728983 has 4 divisors (see below), whose sum is σ = 53527638648. Its totient is φ = 26763819320.

The previous prime is 40145728967. The next prime is 40145728993. The reversal of 40145728983 is 38982754104.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 40145728983 - 24 = 40145728967 is a prime.

It is a super-2 number, since 2×401457289832 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40145728933) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6690954828 + ... + 6690954833.

It is an arithmetic number, because the mean of its divisors is an integer number (13381909662).

Almost surely, 240145728983 is an apocalyptic number.

40145728983 is a deficient number, since it is larger than the sum of its proper divisors (13381909665).

40145728983 is a wasteful number, since it uses less digits than its factorization.

40145728983 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13381909664.

The product of its (nonzero) digits is 1935360, while the sum is 51.

The spelling of 40145728983 in words is "forty billion, one hundred forty-five million, seven hundred twenty-eight thousand, nine hundred eighty-three".

Divisors: 1 3 13381909661 40145728983