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40153643110303 = 147997271313899
BaseRepresentation
bin10010010000100111111111…
…01000100100111110011111
312021011122120102112201000021
421020103333220210332133
520230334130114012203
6221222155021213011
711313001464660562
oct1110237750447637
9167148512481007
1040153643110303
1111881078806988
124606065a01167
13195361a83c498
149cb637a3c4d9
1549974d5765bd
hex2484ffa24f9f

40153643110303 has 4 divisors (see below), whose sum is σ = 40153914572200. Its totient is φ = 40153371648408.

The previous prime is 40153643110249. The next prime is 40153643110307. The reversal of 40153643110303 is 30301134635104.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 40153643110303 - 29 = 40153643109791 is a prime.

It is a super-2 number, since 2×401536431103032 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (40153643110307) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 135508953 + ... + 135804946.

It is an arithmetic number, because the mean of its divisors is an integer number (10038478643050).

Almost surely, 240153643110303 is an apocalyptic number.

40153643110303 is a deficient number, since it is larger than the sum of its proper divisors (271461897).

40153643110303 is a wasteful number, since it uses less digits than its factorization.

40153643110303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 271461896.

The product of its (nonzero) digits is 38880, while the sum is 34.

Adding to 40153643110303 its reverse (30301134635104), we get a palindrome (70454777745407).

The spelling of 40153643110303 in words is "forty trillion, one hundred fifty-three billion, six hundred forty-three million, one hundred ten thousand, three hundred three".

Divisors: 1 147997 271313899 40153643110303