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40179836713 is a prime number
BaseRepresentation
bin100101011010111001…
…111010011100101001
310211201012110012002111
4211122321322130221
51124242014233323
630243001202321
72621456656042
oct453271723451
9124635405074
1040179836713
111604951a025
1279541903a1
133a343ca013
141d324218c9
1510a26abc0d
hex95ae7a729

40179836713 has 2 divisors, whose sum is σ = 40179836714. Its totient is φ = 40179836712.

The previous prime is 40179836699. The next prime is 40179836717. The reversal of 40179836713 is 31763897104.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 37634836009 + 2545000704 = 193997^2 + 50448^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-40179836713 is a prime.

It is a super-2 number, since 2×401798367132 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (40179836717) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20089918356 + 20089918357.

It is an arithmetic number, because the mean of its divisors is an integer number (20089918357).

Almost surely, 240179836713 is an apocalyptic number.

It is an amenable number.

40179836713 is a deficient number, since it is larger than the sum of its proper divisors (1).

40179836713 is an equidigital number, since it uses as much as digits as its factorization.

40179836713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 762048, while the sum is 49.

The spelling of 40179836713 in words is "forty billion, one hundred seventy-nine million, eight hundred thirty-six thousand, seven hundred thirteen".