4020113 has 4 divisors (see below), whose sum is σ = 4113648. Its totient is φ = 3926580.

The previous prime is 4020031. The next prime is 4020119. The reversal of 4020113 is 3110204.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 4020113 - 2¹⁴ = 4003729 is a prime.

It is a super-2 number, since 2×4020113² = 32322617065538, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 4020094 and 4020103.

It is not an unprimeable number, because it can be changed into a prime (4020119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 46703 + ... + 46788.

It is an arithmetic number, because the mean of its divisors is an integer number (1028412).

Almost surely, 2^4020113 is an apocalyptic number.

4020113 is a gapful number since it is divisible by the number (43) formed by its first and last digit.

It is an amenable number.

4020113 is a deficient number, since it is larger than the sum of its proper divisors (93535).

4020113 is an equidigital number, since it uses as much as digits as its factorization.

4020113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 93534.

The product of its (nonzero) digits is 24, while the sum is 11.

The square root of 4020113 is about 2005.0219450171. The cubic root of 4020113 is about 159.0057221415.

Adding to 4020113 its reverse (3110204), we get a palindrome (7130317).

Subtracting from 4020113 its reverse (3110204), we obtain a palindrome (909909).

The spelling of 4020113 in words is "four million, twenty thousand, one hundred thirteen".