Base | Representation |
---|---|
bin | 111010100000000001011… |
… | …011101011001110011011 |
3 | 112020022121121122100211111 |
4 | 322200001123223032123 |
5 | 1011331143013434321 |
6 | 12314451542241151 |
7 | 563305105161106 |
oct | 72400133531633 |
9 | 15208547570744 |
10 | 4020113421211 |
11 | 130aa14249728 |
12 | 54b15ba261b7 |
13 | 232130b359c4 |
14 | dc80870b73d |
15 | 6e88bb7c5e1 |
hex | 3a8016eb39b |
4020113421211 has 2 divisors, whose sum is σ = 4020113421212. Its totient is φ = 4020113421210.
The previous prime is 4020113421089. The next prime is 4020113421221. The reversal of 4020113421211 is 1121243110204.
4020113421211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4020113421211 - 217 = 4020113290139 is a prime.
It is a super-2 number, since 2×40201134212112 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4020113421221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010056710605 + 2010056710606.
It is an arithmetic number, because the mean of its divisors is an integer number (2010056710606).
Almost surely, 24020113421211 is an apocalyptic number.
4020113421211 is a deficient number, since it is larger than the sum of its proper divisors (1).
4020113421211 is an equidigital number, since it uses as much as digits as its factorization.
4020113421211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 22.
Adding to 4020113421211 its reverse (1121243110204), we get a palindrome (5141356531415).
The spelling of 4020113421211 in words is "four trillion, twenty billion, one hundred thirteen million, four hundred twenty-one thousand, two hundred eleven".
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