Base | Representation |
---|---|
bin | 100101011100001011… |
… | …111101000100001011 |
3 | 10211202200220211111122 |
4 | 211130023331010023 |
5 | 1124313020440433 |
6 | 30245050145455 |
7 | 2622140531225 |
oct | 453413750413 |
9 | 124680824448 |
10 | 40201343243 |
11 | 1605a679216 |
12 | 795b42228b |
13 | 3a389ba089 |
14 | 1d3521d415 |
15 | 10a4509198 |
hex | 95c2fd10b |
40201343243 has 2 divisors, whose sum is σ = 40201343244. Its totient is φ = 40201343242.
The previous prime is 40201343207. The next prime is 40201343257. The reversal of 40201343243 is 34234310204.
40201343243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40201343243 - 228 = 39932907787 is a prime.
It is a super-3 number, since 3×402013432433 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (40201343543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20100671621 + 20100671622.
It is an arithmetic number, because the mean of its divisors is an integer number (20100671622).
Almost surely, 240201343243 is an apocalyptic number.
40201343243 is a deficient number, since it is larger than the sum of its proper divisors (1).
40201343243 is an equidigital number, since it uses as much as digits as its factorization.
40201343243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 26.
Adding to 40201343243 its reverse (34234310204), we get a palindrome (74435653447).
The spelling of 40201343243 in words is "forty billion, two hundred one million, three hundred forty-three thousand, two hundred forty-three".
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