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4020170513 is a prime number
BaseRepresentation
bin1110111110011110…
…1110111100010001
3101101011122211012012
43233213232330101
531213130424023
61502530112305
7201423612512
oct35747567421
911334584165
104020170513
111783310677
1294241b695
134c0b64628
142a1cc4a09
15187e0b978
hexef9eef11

4020170513 has 2 divisors, whose sum is σ = 4020170514. Its totient is φ = 4020170512.

The previous prime is 4020170471. The next prime is 4020170533. The reversal of 4020170513 is 3150710204.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2903808769 + 1116361744 = 53887^2 + 33412^2 .

It is a cyclic number.

It is not a de Polignac number, because 4020170513 - 214 = 4020154129 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (4020170533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010085256 + 2010085257.

It is an arithmetic number, because the mean of its divisors is an integer number (2010085257).

Almost surely, 24020170513 is an apocalyptic number.

It is an amenable number.

4020170513 is a deficient number, since it is larger than the sum of its proper divisors (1).

4020170513 is an equidigital number, since it uses as much as digits as its factorization.

4020170513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 840, while the sum is 23.

The square root of 4020170513 is about 63404.8145884837. The cubic root of 4020170513 is about 1590.0648039988.

Adding to 4020170513 its reverse (3150710204), we get a palindrome (7170880717).

The spelling of 4020170513 in words is "four billion, twenty million, one hundred seventy thousand, five hundred thirteen".