Base | Representation |
---|---|
bin | 111010100000000110110… |
… | …101111110100000110001 |
3 | 112020022211221110111201011 |
4 | 322200012311332200301 |
5 | 1011331334233431113 |
6 | 12314504544110521 |
7 | 563310256615165 |
oct | 72400665764061 |
9 | 15208757414634 |
10 | 4020204202033 |
11 | 130aa605136a8 |
12 | 54b186305441 |
13 | 23214689c176 |
14 | dc8167bcca5 |
15 | 6e894b1063d |
hex | 3a806d7e831 |
4020204202033 has 2 divisors, whose sum is σ = 4020204202034. Its totient is φ = 4020204202032.
The previous prime is 4020204201973. The next prime is 4020204202037. The reversal of 4020204202033 is 3302024020204.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3399775447104 + 620428754929 = 1843848^2 + 787673^2 .
It is a cyclic number.
It is not a de Polignac number, because 4020204202033 - 237 = 3882765248561 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4020204201995 and 4020204202013.
It is not a weakly prime, because it can be changed into another prime (4020204202037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010102101016 + 2010102101017.
It is an arithmetic number, because the mean of its divisors is an integer number (2010102101017).
Almost surely, 24020204202033 is an apocalyptic number.
It is an amenable number.
4020204202033 is a deficient number, since it is larger than the sum of its proper divisors (1).
4020204202033 is an equidigital number, since it uses as much as digits as its factorization.
4020204202033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 22.
Adding to 4020204202033 its reverse (3302024020204), we get a palindrome (7322228222237).
The spelling of 4020204202033 in words is "four trillion, twenty billion, two hundred four million, two hundred two thousand, thirty-three".
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