Base | Representation |
---|---|
bin | 1011101100110100110… |
… | …00011000001001000011 |
3 | 1102102200121101122121001 |
4 | 11312122120120021003 |
5 | 23041320120241011 |
6 | 504404131312431 |
7 | 41021323646515 |
oct | 5663230301103 |
9 | 1372617348531 |
10 | 402022040131 |
11 | 145550a63048 |
12 | 65ab844b717 |
13 | 2bbab5315aa |
14 | 1565a957bb5 |
15 | a6ce1b17c1 |
hex | 5d9a618243 |
402022040131 has 2 divisors, whose sum is σ = 402022040132. Its totient is φ = 402022040130.
The previous prime is 402022040093. The next prime is 402022040149. The reversal of 402022040131 is 131040220204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 402022040131 - 215 = 402022007363 is a prime.
It is a super-2 number, since 2×4020220401312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 402022040099 and 402022040108.
It is not a weakly prime, because it can be changed into another prime (402022040171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201011020065 + 201011020066.
It is an arithmetic number, because the mean of its divisors is an integer number (201011020066).
Almost surely, 2402022040131 is an apocalyptic number.
402022040131 is a deficient number, since it is larger than the sum of its proper divisors (1).
402022040131 is an equidigital number, since it uses as much as digits as its factorization.
402022040131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 402022040131 its reverse (131040220204), we get a palindrome (533062260335).
The spelling of 402022040131 in words is "four hundred two billion, twenty-two million, forty thousand, one hundred thirty-one".
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