Base | Representation |
---|---|
bin | 111010100001001001100… |
… | …110110100101111100011 |
3 | 112020102202000010112211102 |
4 | 322201021212310233203 |
5 | 1011341133010201311 |
6 | 12315212035505015 |
7 | 563350110411506 |
oct | 72411146645743 |
9 | 15212660115742 |
10 | 4021324303331 |
11 | 1310485808355 |
12 | 54b43945816b |
13 | 23229496a3ba |
14 | dc8c147113d |
15 | 6e90d11743b |
hex | 3a8499b4be3 |
4021324303331 has 2 divisors, whose sum is σ = 4021324303332. Its totient is φ = 4021324303330.
The previous prime is 4021324303319. The next prime is 4021324303379. The reversal of 4021324303331 is 1333034231204.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4021324303331 is a prime.
It is a super-2 number, since 2×40213243033312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 4021324303294 and 4021324303303.
It is not a weakly prime, because it can be changed into another prime (4021324303631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010662151665 + 2010662151666.
It is an arithmetic number, because the mean of its divisors is an integer number (2010662151666).
Almost surely, 24021324303331 is an apocalyptic number.
4021324303331 is a deficient number, since it is larger than the sum of its proper divisors (1).
4021324303331 is an equidigital number, since it uses as much as digits as its factorization.
4021324303331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 4021324303331 its reverse (1333034231204), we get a palindrome (5354358534535).
The spelling of 4021324303331 in words is "four trillion, twenty-one billion, three hundred twenty-four million, three hundred three thousand, three hundred thirty-one".
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