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402141110403233 is a prime number
BaseRepresentation
bin101101101101111101100011…
…0000010010000000010100001
31221201212022111102020011201202
41123123323012002100002201
5410202134443230400413
63543141024205410545
7150463510413032045
oct13333730602200241
91851768442204652
10402141110403233
111071530a6030a43
1239129784269a55
1314350989728036
147143a3adb2025
15317592e56ae58
hex16dbec60900a1

402141110403233 has 2 divisors, whose sum is σ = 402141110403234. Its totient is φ = 402141110403232.

The previous prime is 402141110403121. The next prime is 402141110403271. The reversal of 402141110403233 is 332304011141204.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 395544596219809 + 6596514183424 = 19888303^2 + 2568368^2 .

It is a cyclic number.

It is not a de Polignac number, because 402141110403233 - 212 = 402141110399137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 402141110403196 and 402141110403205.

It is not a weakly prime, because it can be changed into another prime (402141110403533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201070555201616 + 201070555201617.

It is an arithmetic number, because the mean of its divisors is an integer number (201070555201617).

Almost surely, 2402141110403233 is an apocalyptic number.

It is an amenable number.

402141110403233 is a deficient number, since it is larger than the sum of its proper divisors (1).

402141110403233 is an equidigital number, since it uses as much as digits as its factorization.

402141110403233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 402141110403233 its reverse (332304011141204), we get a palindrome (734445121544437).

The spelling of 402141110403233 in words is "four hundred two trillion, one hundred forty-one billion, one hundred ten million, four hundred three thousand, two hundred thirty-three".