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4021423010131 is a prime number
BaseRepresentation
bin111010100001001111011…
…111010111000101010011
3112020102222212212101002211
4322201033133113011103
51011341333242311011
612315225523252551
7563352416406442
oct72411737270523
915212885771084
104021423010131
1113105264a621a
1254b46651a157
132322ac24a3a7
14dc8d0606d59
156e916b13b21
hex3a84f7d7153

4021423010131 has 2 divisors, whose sum is σ = 4021423010132. Its totient is φ = 4021423010130.

The previous prime is 4021423010089. The next prime is 4021423010147. The reversal of 4021423010131 is 1310103241204.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4021423010131 - 233 = 4012833075539 is a prime.

It is a super-2 number, since 2×40214230101312 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4021423010431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010711505065 + 2010711505066.

It is an arithmetic number, because the mean of its divisors is an integer number (2010711505066).

Almost surely, 24021423010131 is an apocalyptic number.

4021423010131 is a deficient number, since it is larger than the sum of its proper divisors (1).

4021423010131 is an equidigital number, since it uses as much as digits as its factorization.

4021423010131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 4021423010131 its reverse (1310103241204), we get a palindrome (5331526251335).

The spelling of 4021423010131 in words is "four trillion, twenty-one billion, four hundred twenty-three million, ten thousand, one hundred thirty-one".