Base | Representation |
---|---|
bin | 111010100001001111011… |
… | …111110010011110000011 |
3 | 112020102222220002001222111 |
4 | 322201033133302132003 |
5 | 1011341333304403212 |
6 | 12315225525520151 |
7 | 563352420354463 |
oct | 72411737623603 |
9 | 15212886061874 |
10 | 4021423122307 |
11 | 1310526572528 |
12 | 54b466573057 |
13 | 2322ac289476 |
14 | dc8d0635ba3 |
15 | 6e916b36ea7 |
hex | 3a84f7f2783 |
4021423122307 has 2 divisors, whose sum is σ = 4021423122308. Its totient is φ = 4021423122306.
The previous prime is 4021423122221. The next prime is 4021423122347. The reversal of 4021423122307 is 7032213241204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4021423122307 - 231 = 4019275638659 is a prime.
It is not a weakly prime, because it can be changed into another prime (4021423122347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2010711561153 + 2010711561154.
It is an arithmetic number, because the mean of its divisors is an integer number (2010711561154).
Almost surely, 24021423122307 is an apocalyptic number.
4021423122307 is a deficient number, since it is larger than the sum of its proper divisors (1).
4021423122307 is an equidigital number, since it uses as much as digits as its factorization.
4021423122307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 31.
The spelling of 4021423122307 in words is "four trillion, twenty-one billion, four hundred twenty-three million, one hundred twenty-two thousand, three hundred seven".
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