Base | Representation |
---|---|
bin | 111010100001110010100… |
… | …110001101111110100011 |
3 | 112020111111221011200120201 |
4 | 322201302212031332203 |
5 | 1011344040033313103 |
6 | 12315404203450031 |
7 | 563403131003422 |
oct | 72416246157643 |
9 | 15214457150521 |
10 | 4022012010403 |
11 | 13107a8a20902 |
12 | 54b5ab826917 |
13 | 23237429436a |
14 | dc9489292b9 |
15 | 6e94d6ac51d |
hex | 3a87298dfa3 |
4022012010403 has 2 divisors, whose sum is σ = 4022012010404. Its totient is φ = 4022012010402.
The previous prime is 4022012010383. The next prime is 4022012010449. The reversal of 4022012010403 is 3040102102204.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4022012010403 is a prime.
It is a super-2 number, since 2×40220120104032 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4022012010473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011006005201 + 2011006005202.
It is an arithmetic number, because the mean of its divisors is an integer number (2011006005202).
Almost surely, 24022012010403 is an apocalyptic number.
4022012010403 is a deficient number, since it is larger than the sum of its proper divisors (1).
4022012010403 is an equidigital number, since it uses as much as digits as its factorization.
4022012010403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 19.
Adding to 4022012010403 its reverse (3040102102204), we get a palindrome (7062114112607).
The spelling of 4022012010403 in words is "four trillion, twenty-two billion, twelve million, ten thousand, four hundred three".
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