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402202100201323 is a prime number
BaseRepresentation
bin101101101110011001111100…
…1010011110111011101101011
31221202002010220220021221012111
41123130303321103313131223
5410204134400122420243
63543225032152423151
7150501066661540342
oct13334637123673553
91852063826257174
10402202100201323
11107176a531a3a54
12391395656a7ab7
131435665925c966
1471469850b8b59
1531772edb3739d
hex16dccf94f776b

402202100201323 has 2 divisors, whose sum is σ = 402202100201324. Its totient is φ = 402202100201322.

The previous prime is 402202100201287. The next prime is 402202100201357. The reversal of 402202100201323 is 323102001202204.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-402202100201323 is a prime.

It is a super-3 number, since 3×4022021002013233 (a number of 45 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 402202100201294 and 402202100201303.

It is not a weakly prime, because it can be changed into another prime (402202100201383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 201101050100661 + 201101050100662.

It is an arithmetic number, because the mean of its divisors is an integer number (201101050100662).

Almost surely, 2402202100201323 is an apocalyptic number.

402202100201323 is a deficient number, since it is larger than the sum of its proper divisors (1).

402202100201323 is an equidigital number, since it uses as much as digits as its factorization.

402202100201323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 402202100201323 its reverse (323102001202204), we get a palindrome (725304101403527).

The spelling of 402202100201323 in words is "four hundred two trillion, two hundred two billion, one hundred million, two hundred one thousand, three hundred twenty-three".