Base | Representation |
---|---|
bin | 111010100001110011001… |
… | …101111001101101100001 |
3 | 112020111112122202012110202 |
4 | 322201303031321231201 |
5 | 1011344100214210103 |
6 | 12315405214434545 |
7 | 563403315301223 |
oct | 72416315715541 |
9 | 15214478665422 |
10 | 4022022413153 |
11 | 1310803886618 |
12 | 54b5b3202a55 |
13 | 232376497334 |
14 | dc94a076413 |
15 | 6e94e564988 |
hex | 3a873379b61 |
4022022413153 has 2 divisors, whose sum is σ = 4022022413154. Its totient is φ = 4022022413152.
The previous prime is 4022022413111. The next prime is 4022022413203. The reversal of 4022022413153 is 3513142202204.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4015082190289 + 6940222864 = 2003767^2 + 83308^2 .
It is a cyclic number.
It is not a de Polignac number, because 4022022413153 - 28 = 4022022412897 is a prime.
It is not a weakly prime, because it can be changed into another prime (4022022403153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011011206576 + 2011011206577.
It is an arithmetic number, because the mean of its divisors is an integer number (2011011206577).
Almost surely, 24022022413153 is an apocalyptic number.
It is an amenable number.
4022022413153 is a deficient number, since it is larger than the sum of its proper divisors (1).
4022022413153 is an equidigital number, since it uses as much as digits as its factorization.
4022022413153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 11520, while the sum is 29.
Adding to 4022022413153 its reverse (3513142202204), we get a palindrome (7535164615357).
The spelling of 4022022413153 in words is "four trillion, twenty-two billion, twenty-two million, four hundred thirteen thousand, one hundred fifty-three".
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