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4022157133537 is a prime number
BaseRepresentation
bin111010100001111011001…
…111110100011011100001
3112020111220001020201002121
4322201323033310123201
51011344334211233122
612315430430144241
7563406542352064
oct72417317643341
915214801221077
104022157133537
111310872931a84
1254b630352081
1323239837653a
14dc95dd048db
156e95b2c6bc7
hex3a87b3f46e1

4022157133537 has 2 divisors, whose sum is σ = 4022157133538. Its totient is φ = 4022157133536.

The previous prime is 4022157133499. The next prime is 4022157133543. The reversal of 4022157133537 is 7353317512204.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3763914286561 + 258242846976 = 1940081^2 + 508176^2 .

It is a cyclic number.

It is not a de Polignac number, because 4022157133537 - 27 = 4022157133409 is a prime.

It is a super-3 number, since 3×40221571335373 (a number of 39 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 4022157133493 and 4022157133502.

It is not a weakly prime, because it can be changed into another prime (4022157133237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011078566768 + 2011078566769.

It is an arithmetic number, because the mean of its divisors is an integer number (2011078566769).

Almost surely, 24022157133537 is an apocalyptic number.

It is an amenable number.

4022157133537 is a deficient number, since it is larger than the sum of its proper divisors (1).

4022157133537 is an equidigital number, since it uses as much as digits as its factorization.

4022157133537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 529200, while the sum is 43.

The spelling of 4022157133537 in words is "four trillion, twenty-two billion, one hundred fifty-seven million, one hundred thirty-three thousand, five hundred thirty-seven".