4023012113 has 2 divisors, whose sum is σ = 4023012114. Its totient is φ = 4023012112.

The previous prime is 4023012083. The next prime is 4023012121. The reversal of 4023012113 is 3112103204.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4017404689 + 5607424 = 63383^2 + 2368^2 .

It is a cyclic number.

It is not a de Polignac number, because 4023012113 - 2²⁶ = 3955903249 is a prime.

It is a super-2 number, since 2×4023012113² = 32369252922689449538, which contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 4023012091 and 4023012100.

It is not a weakly prime, because it can be changed into another prime (4023012613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011506056 + 2011506057.

It is an arithmetic number, because the mean of its divisors is an integer number (2011506057).

Almost surely, 2^4023012113 is an apocalyptic number.

It is an amenable number.

4023012113 is a deficient number, since it is larger than the sum of its proper divisors (1).

4023012113 is an equidigital number, since it uses as much as digits as its factorization.

4023012113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 4023012113 is about 63427.2190230661. The cubic root of 4023012113 is about 1590.4393539487.

Adding to 4023012113 its reverse (3112103204), we get a palindrome (7135115317).

The spelling of 4023012113 in words is "four billion, twenty-three million, twelve thousand, one hundred thirteen".