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40231100011313 is a prime number
BaseRepresentation
bin10010010010111000010000…
…11011001101001100110001
312021110001111112100222000202
421021130020123031030301
520233121243100330223
6221321525011324545
711321413106530451
oct1111341033151461
9167401445328022
1040231100011313
1111900a06152062
124619081bb0755
13195aa12b348a3
149d12a4b47d61
1549b783654428
hex2497086cd331

40231100011313 has 2 divisors, whose sum is σ = 40231100011314. Its totient is φ = 40231100011312.

The previous prime is 40231100011237. The next prime is 40231100011327. The reversal of 40231100011313 is 31311000113204.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 27971066957824 + 12260033053489 = 5288768^2 + 3501433^2 .

It is a cyclic number.

It is not a de Polignac number, because 40231100011313 - 214 = 40231099994929 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (40231100011013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20115550005656 + 20115550005657.

It is an arithmetic number, because the mean of its divisors is an integer number (20115550005657).

Almost surely, 240231100011313 is an apocalyptic number.

It is an amenable number.

40231100011313 is a deficient number, since it is larger than the sum of its proper divisors (1).

40231100011313 is an equidigital number, since it uses as much as digits as its factorization.

40231100011313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 40231100011313 its reverse (31311000113204), we get a palindrome (71542100124517).

The spelling of 40231100011313 in words is "forty trillion, two hundred thirty-one billion, one hundred million, eleven thousand, three hundred thirteen".