Base | Representation |
---|---|
bin | 111010100010111011010… |
… | …100011111111011101001 |
3 | 112020121122221222202202212 |
4 | 322202323110133323221 |
5 | 1011404034404231441 |
6 | 12320125230334505 |
7 | 563445304422221 |
oct | 72427324377351 |
9 | 15217587882685 |
10 | 4023232102121 |
11 | 13112746aa871 |
12 | 54b89035a435 |
13 | 232509ca191b |
14 | dca229a9081 |
15 | 6e9c0865eeb |
hex | 3a8bb51fee9 |
4023232102121 has 2 divisors, whose sum is σ = 4023232102122. Its totient is φ = 4023232102120.
The previous prime is 4023232102069. The next prime is 4023232102129. The reversal of 4023232102121 is 1212012323204.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3010519957225 + 1012712144896 = 1735085^2 + 1006336^2 .
It is a cyclic number.
It is not a de Polignac number, because 4023232102121 - 226 = 4023164993257 is a prime.
It is not a weakly prime, because it can be changed into another prime (4023232102129) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2011616051060 + 2011616051061.
It is an arithmetic number, because the mean of its divisors is an integer number (2011616051061).
Almost surely, 24023232102121 is an apocalyptic number.
It is an amenable number.
4023232102121 is a deficient number, since it is larger than the sum of its proper divisors (1).
4023232102121 is an equidigital number, since it uses as much as digits as its factorization.
4023232102121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 4023232102121 its reverse (1212012323204), we get a palindrome (5235244425325).
The spelling of 4023232102121 in words is "four trillion, twenty-three billion, two hundred thirty-two million, one hundred two thousand, one hundred twenty-one".
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