Base | Representation |
---|---|
bin | 10010010010111100001011… |
… | …01010110001100010010011 |
3 | 12021110020220222012122210222 |
4 | 21021132011222301202103 |
5 | 20233140044004304212 |
6 | 221322513312143255 |
7 | 11321516142651251 |
oct | 1111360552614223 |
9 | 167406828178728 |
10 | 40233201244307 |
11 | 11901894252555 |
12 | 4619569837b2b |
13 | 195ac89264a16 |
14 | 9d1423c355d1 |
15 | 49b857d61c72 |
hex | 249785ab1893 |
40233201244307 has 2 divisors, whose sum is σ = 40233201244308. Its totient is φ = 40233201244306.
The previous prime is 40233201244259. The next prime is 40233201244319. The reversal of 40233201244307 is 70344210233204.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 40233201244307 - 210 = 40233201243283 is a prime.
It is not a weakly prime, because it can be changed into another prime (40233201244367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 20116600622153 + 20116600622154.
It is an arithmetic number, because the mean of its divisors is an integer number (20116600622154).
Almost surely, 240233201244307 is an apocalyptic number.
40233201244307 is a deficient number, since it is larger than the sum of its proper divisors (1).
40233201244307 is an equidigital number, since it uses as much as digits as its factorization.
40233201244307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96768, while the sum is 35.
The spelling of 40233201244307 in words is "forty trillion, two hundred thirty-three billion, two hundred one million, two hundred forty-four thousand, three hundred seven".
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